8x^2+8x-143=0

Solution for 8x^2+8x-143=0 equation:

8x^2+8x-143=0

a = 8; b = 8; c = -143;
Δ = b2-4ac
Δ = 82-4·8·(-143)
Δ = 4640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4640}=\sqrt{16*290}=\sqrt{16}*\sqrt{290}=4\sqrt{290}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{290}}{2*8}=\frac{-8-4\sqrt{290}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{290}}{2*8}=\frac{-8+4\sqrt{290}}{16}
$